Telecom n Networking Bits n Bites

Antenna Directivity

2009-09-24T10:16:00.000-07:00

Directivity is the ratio of radiation intensity to the radiation intensity averaged over a sphere.It is different from gain although both terms are used interchangeably. Directivity is also different from beamwidth and is calculated using the beamwidth angles at half-power as follows,

D = 40,000 / (theta * phi)

where

theta = E-plane half-power beamwidth angle in degrees
phi = H-plane half-power beamwidth angle in degrees

Directivity can also be calculated if the aperture size and wavelength are known as follows,

D = 4* PI * A / lamda^2

where A = aperture area, lambda = wave length and PI=3.14

Beamwidth Calculations

2009-09-24T09:33:00.001-07:00

Beamwidth is an important antenna parameter. Beamwidth is inversely proportional to antenna gain and hence inversely proportional to antenna size.

The beamwidth distance of a simple directional antenna at distance d from the antenna of a beamwidth angle of α, can be calculated using the following formula:

2dtan(α/2)

d = distance and α = angle

There is no formula that fits all types of antennae for beamwidth angle calculation, however a formula that can be used for parabolic antennae is:

Beamwidth = 70 * lambda / d

where lamba = the wavelength, d = the antennae diameter

Several online beamwidth calculators are available:

- Parabolic beamwidth calculator by Eric Johnston
- NOAA's beam property calculator

Poynting Vector

2009-09-24T07:56:00.000-07:00

The Poynting vector is used to define power patterns in electromagnetic waves. It points in the direction of the wave propagation and its amplitude is calculated by multiplying the amplitudes of the electric and magnetic fields divided by the permeability of the medium in which the wave flows.

S = 1/u * EB

where

S is the Poynting vector amplitude

E = the electric field amplitude
B = the magnetic field amplitude
u = the permeability of the medium (4*PI* 10^-7 H/m for vacuum)

Antenna Near-Field

2009-08-20T13:17:00.000-07:00

Surrounding antennas are two spatial fields; the near field and far field. Near-field region contains reactive and oscillating electromagnetic field, while the far-field region contains only transverse-propagating electromagnetic fields.

The near-field is calculated by the formula on the right, where r is the furthest point in the near-field, D is the largest dimension of the antenna and lambda is the wavelength.

Reactive fields are formed by stationary charges or charges moving at uniform velocity. Examples are DC power sources as they cause a constant drift of charges resulting in a reactive field. AC sources also produce reactive fields in addition to radiating fields. Reactive fields store energy capacitively and/or inductively in the absence of a receiving circuit or antenna. If an antenna or receiving circuit is present, a reactive field will lead transfer energy through capacitive or inductive coupling.

Reactive fields characteristics are very dependent on the source of the energy, and is extinguished once the source is inactive. Reactive fields do not propagate and measuring these fields impacts the source voltage and currents. Reactive fields impedance and wave shape are dependent on the source and energy can be transported using transmission lines.
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Read more:
[1] Ron Schmitt, "Electromagnetics Explained: A Handbook for Wireless /RF, EMC and High Speed Electronics", Newnes, 2002.

MRI

2007-01-02T21:24:00.000-08:00

http://looly.net/articles/2006/12/10/magnetic-resonance-imaging/

Electromagnetic Frequencies

2007-01-02T21:16:00.000-08:00

An interesting blog that discusses EMF and radiation is located at: http://cellphonesafety.wordpress.com/2006/09/02/wifi-emits-microwave-radiation/

ELECTROMAGNETIC RADIATION AND KIDS

2006-09-26T21:48:00.000-07:00

Experts are calling for reduced exposure of kids to electromagnetic devices deemed dangerous, perhaps most of all, cell phones. A new report released by the American Academy of Pediatrics suggests that there is indeed an increased cancer risk, but it’s still a bit hazy how significant that cancer risk might be. This two-minute video clip discusses the issue. Says Dr. Mark Atlas, a pediatric oncologist at Schneider Children’s Hospital, in an interview, “One of the concerns for children is that they will be exposed to this for many more years of their lives. Adults who start using a cell phone at age 40 or 50 will be exposed for 30 or 40 years. A child who is exposed now is going to be exposed at a younger age for a life time, and is thus at a significant cancer risk.”

A cell tower in the school yard

2006-05-29T19:14:00.000-07:00

The school called and mentioned that they have been approached by the mobile phone company with a proposal to install a tower in the school yard !!

Hmmm... What impact will that have on,

1. The kids health
2. The school's propoerty value
3. The real-estate value in the neighborhood
4. The environment
5. Safety

Have you had a similiar experience? Drop me a note.